Example3 Cantilever with Forced Displacement

General

  • The free end of a cantilever is displaced forcibly.
     

  • The distributions of displacement and mechanical stress are solved.
     

  • Unless specified in the list below, the default conditions will be applied.
     

 

Analysis Space

Item

Settings

Analysis Space

3D

Model unit

m

 

Analysis Conditions

 

Item

Settings

Solver

Mechanical Stress Analysis [Galileo]

Analysis Type

Static analysis

Options

N/A

 Model

The rectangle bar is a solid body. The material is polycarbonate.

On the mechanical tab in the boundary condition dialog box, set the zero displacement on the fixed face, and also set the forced displacement in the negative Z direction on the edge topology of the other end.

 

Body Attributes and Materials

Body Number/Type

Body Attribute Name

Material Name

0/Solid

BEAM

002_Polycarbonate(PC) *

* Available from the Material DB

Boundary Conditions

Boundary Condition Name/Topology

Tab

Boundary Condition Type

Settings

FIX/Face

Mechanical

Displacement

Select all X/Y/Z components.

UX=0, UY=0, UZ=0

DISP/Edge

Mechanical

Displacement

Select the Z-direction component.

UZ=-0.5×10^-3[m]

Results

The contour diagram shows the displacement.

The displacement is bigger towards the tip of the bar. The displacement at the tip is 500[um] as specified.

 

The vectors of the mechanical stress are shown below.

The upper part of the fixed end is getting the tensile stress, whereas the lower part is getting the compression stress.

 

The external force and reactive force are listed in the table below.

 

 

The reactive force at FIX is 445[N] in +Z direction.

The external force at DISP is 445[N] in -Z direction.