Example5 Ring under Forced Normal Displacement

General

  • A ring is deformed due to the forced normal displacement.
     

  • The distributions of displacement and mechanical stress are solved.
     

  • Unless specified in the list below, the default conditions will be applied.
     

 

Analysis Space

Item

Settings

Analysis Space

3D

Model unit

mm

 

Analysis Conditions

This is a static analysis.

Item

Settings

Solvers

Mechanical Stress Analysis [Galileo]

Analysis Type

Static analysis

Options

N/A

 Model

Two cylindrical solid bodies are created. The smaller cylinder is subtracted from the larger cylinder by boolean. As a result, a ring is created.

The inner face of the ring is set with the simple contact boundary condition.

 

Body Attributes and Materials

Body Number/Type

Body Attribute Name

Material Name

0/Solid

RING

001_Al *

* Available from the Material DB

Boundary Conditions

The normal displacement is set as follows:

Boundary Condition Name/Topology

Tab

Boundary Condition Type

Settings

DISP/Face

Mechanical

Normal displacement

0.5×10^-3[m]

Results

The vectors of the displacement are shown below.

The inner side of the ring is displaced by 0.5[mm]. The outer side is displaced less.

 

The vectors of the mechanical stress are shown below.

The tensile stress is exhibited in the circumferential direction, while the compressive stress is exhibited in the radial direction.