Example34 Energy Release Rate

General

 

  • A plate with a crack is expanded and the mechanical stresses are analyzed.

  • From the resulting strain energy, the energy release rate and the stress intensity factor are calculated.

  • See Exercise 46: Energy Release Rate Calculated by J Integral for another way to solve it.

  • Unless specified in the list below, the default conditions will be applied.

 

Analysis Space

Item

Settings

Analysis Space

2D

Model unit

mm

 

Analysis Conditions

Item

Settings

Solver

Mechanical Stress Analysis [Galileo]

Analysis Type

Static analysis

Options

N/A

 

Model

A plate with a crack is expanded and the mechanical stresses are analyzed.

The tensile strength can be evaluated by the stress intensity factor, K.

The theoretical value of K is given by the equation below.

 

We acquire K through the simulation and compare it with the theoretical value.

 

 

 

 

 

The model is symmetric vertically and horizontally. Therefore a quarter of the model is analyzed.

Select [Reflective] on the Symmetry/Continuity tab for each face of symmetry.

 

 

 

 

Body Attributes and Materials

Body Number/Type

Body Attribute Name

Material Name

0/Sheet

Plate

Fe

 

The thickness of sheet body is set to 1[m].

Body Attribute Name

Tab

Settings

Plate

Thickness/Width

Thickness of Sheet Body: 1000

 

Set Young’s modulus and Poisson’s ratio.

Material Name

Young’s modulus

Poisson’s ratio.

PlateMat*

70.56×10^9[Pa]

0.33

*Depends on the material.

Boundary Conditions

Boundary Condition Name/Topology

Tab

Boundary Condition Type

Settings

Sym_X/Edge

Symmetry/Continuity

Symmetry

Reflective

Sym_Z/Edge

Mechanical

Symmetry

Reflective

P/Edge

Mechanical

Pressure

-98×10^6[Pa]

 

Results

In the figure below, the maximum principal stress is superposed on displacement diagram.

The color scale range is 0 to 400MPa.

The full model can be viewed.

High stress is exhibited at the end of the crack.

 

 

 

 

Energy Release Rate

It is not practical to directly relate the stress to the ultimate tensile strength,

since the stress depends on the meshing.

It is common to use the energy release rate and the stress intensity factor to estimate the ultimate tensile strength.

 

The energy release rate (g) is given by the following equation in terms of the strain energy (U) and the length (a).

 

(1)

 

Here, the length changes from a=4.05 to a=3.95.

With this quarter model, U=12.1805977[J] at a=4.05[mm] and

U=12.0728236 at a=3.95. So for the full model,

 

(2)

 

Note that it is multiplied by 4 as the full model’s energy is 4 times as much as the quarter model’s energy.

Also note that it is divided by 2 as the full model’s crack is twice as long as the quarter model’s crack.

 

Stress Intensity Factor

In case of 2D, the energy release rate, g and the stress intensity factor, K have the following relationship.

 

Planar stress

 

(3)

 

Planar strain

 

(4)

 

Equation (3) is applicable for this exercise. By using Equation (2), we get the following.

 

(5)

 

This value matches quite well with the theoretical value.