Home / Examples / Electric Analysis [Coulomb] / Example 13: Anisotropic Dielectric Material

Example 13: Anisotropic Dielectric Material

General

• An anisotropic dielectric material is placed in an isotropic dielectric material.
   

• By applying an electric potential difference, the electric field is generated.
  The distributions of the electric field and the current density are solved.
   

• Unless specified in the list below, the default conditions will be applied.
   

• Obtain this session's project file. (Right-click and choose 'Save link as')




• Results will vary depending on Femtet version and the PC environment.

 

Analysis Space

Item	Settings
Analysis Space	3D
Model Unit	mm

 

 

Analysis Conditions

Select [Static Analysis] as the electric potential is static.

Select a dielectric material for analysis.

Item	Settings
Solver	Electric Analysis [Coulomb]
Analysis Type	Static Analysis (Capacitance)
Options	N/A

 

To create the air domain manually, deselect the automatic creation.

Tab	Setting Item	Settings
Mesh Tab	Air Domain Creation	Create air domain automatically: Deselect

Model

The anisotropic dielectric material, Block, is oriented in the X direction.
Air is angled 45 deg with referenced to Block.

Body Attributes and Materials

Body Number/Type	Body Attribute Name	Material Name
0/Solid	Air	000_Air(*)
1/Solid	Block	Anisotropic_Eps

* Available from the material DB

 

The conductivity of the anisotropic conductor is set as follows.

Material Name	Permittivity
Anisotropic_Eps	Anisotropy: Select [Anisotropic].   The [Relative Permittivity Matrix] is set as follows. * 10.0 - - 0.0 1.0 - 0.0 0.0 1.0   * This is not the actual material's property.

Boundary Conditions

Boundary Condition Name/Topology	Tab	Boundary Condition Type	Settings
V0/Face	Electric	Electric Wall	Electric Potential Specified 0 [V]
V1/Face	Electric	Electric Wall	Electric Potential Specified 1 [V]

Results

The vectors of the electric field are shown below.

Also shown are the vectors of the electric flux density.

 

 

These two types of vectors are not parallel due to the anisotropy.

 

• This example shows by applying the electric field in the direction of (1,1,0), the effect of the anisotropic relative permittivity can be calculated.
  Alternatively, by creating a body (Air) with edges in parallel with the coordinate axis, and setting the Euler angle of (0, 0, 45) to the body of anisotropic material
  , the same results can be obtained.