Home / Examples / Coupled Analysis / Thermal-Stress Analysis [Watt/Galileo] / Example 2: Deformation due to the Temperature Gradient #2 - Multiple Materials
Example 2: Deformation due to the Temperature Gradient #2 - Multiple Materials

General
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A heat source is placed on a substrate to cause a temperature gradient. The temperature distribution is calculated using the thermal analysis with
forced air flow cooling taken into account. The resulting thermal expansion is analyzed by the stress analysis.
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The temperature distribution is calculated using the thermal analysis [Watt].
The result is forwarded to the stress analysis [Galileo] as a thermal load corresponding to the reached temperature.
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The deformation, the displacement and the stress are solved.
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Unless specified in the list below, the default conditions will be applied.
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Obtain this session's project file. (Right-click and choose 'Save link as')
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Results will vary depending on Femtet version and the PC environment.
Analysis Space
|
Item |
Settings |
|
Analysis Space |
3D |
|
Model Unit |
mm |
Analysis Conditions
The coupled analysis of the thermal analysis [Watt] and the stress analysis [Galileo] is performed.
|
Item |
Settings |
|
Solver |
Thermal Analysis [Watt] |
|
Thermal-Analysis Type |
Steady-State Analysis |
|
Options |
N/A * |
* [Thermal Load] is selected by default for the thermal-stress coupled analysis.
The Step/Thermal Load tab is set as follows.
|
Tab |
Setting Item |
Settings |
|
Step/Thermal Load * |
Reference Temperature |
25 [deg] |
* The reached temperatures come from the thermal analysis.
Model
The same as example 7 of thermal analysis.

Body Attributes and Materials
|
Body Number/Type |
Body Attribute Name |
Material Name |
|
0/Solid |
VOL1 |
006_Glass_epoxy * |
|
1/Solid |
VOL2 |
001_Alumina * |
* Available from the material DB
Boundary Conditions
The coefficient of heat transfer for the forced convection is calculated as follows.
h = 3.86 x (V/L)0.5xC [W/m2/deg]
where
Air flow V=1 [m/s]
Top and Bottom Faces of VOL1: Typical Length L =0.05, C=1 -> h=17.26
Top Face of VOL2: Typical Length L=0.02, L'=0.015, C=1 * -> h=27.3
*
The thickness (d) of the speed boundary layer at the edges of the heat source is calculated as follows
δ = 0.0182 x (L’/V)0.5= 2.3 [mm]
This is close enough to the thickness of heat source, so we set C=1.
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Boundary Condition Name/Topology |
Tab |
Boundary Condition Type |
Settings |
|
BC1/Face |
Thermal |
Heat Transfer/Convection |
Coefficient of Heat Transfer: 17.26 [W/m2/deg] Ambient Temperature: 25 [deg] |
|
BC2/Face |
Thermal |
Heat Transfer/Convection |
Coefficient of Heat Transfer: 27.3 [W/m2/deg] Ambient Temperature: 25 [deg] |
Thermal analysis is performed based on the boundary conditions below. The resulting temperature distribution is forwarded to stress analysis.
Results
The temperature distribution as a result of Watt is shown below.

The next figure shows the vectors of displacement as a result of Galileo following Watt.

The temperature gradient results in deformation, warping at the four corners of the substrate.


