Home / Examples / Thermal Analysis [Watt] / Example 13: Heat Flux

Example 13: Heat Flux

General

• Two rods with different thermal conductivities are placed closely and subjected to the common [Heat Flux] boundary condition.
   

• The temperature distribution and the heat flux vectors are solved.
   

• Unless specified in the list below, the default conditions will be applied.
   

• Obtain this session's project file. (Right-click and choose 'Save link as')




• Results will vary depending on Femtet version and the PC environment.

 

Analysis Space

Item	Settings
Analysis Space	3D
Model Unit	mm

 

Analysis Conditions

Item	Settings
Solver	Thermal Analysis [Watt]
Analysis Type	Steady-state Analysis
Options	N/A

 

Tab	Setting Item	Settings
Mesh Tab	Meshing Control	Select Place middle nodes on the curve to make smooth cylinders.

 

Model

Two cylindrical solid bodies are created. One is of copper and the other is of nickel. Their thermal conductivities are different.

The [Heat Flux] and [Temperature] boundary conditions are set on the top and bottom faces, respectively.

Body Attributes and Materials

Body Number/Type	Body Attribute Name	Material Name
0/Solid	ROD	008_Cu *
1/Solid	ROD	010_Ni *

* Available from the material DB

 

Boundary Conditions

Boundary Condition Name/Topology	Tab	Boundary Condition Type	Settings
25degree/Face	Thermal	Temperature	25 [deg]
HeatFlux/Face	Thermal	Heat Flux	100000 [W/m2]

* The positive value means the heat flux directs inward.

Results

The temperature distribution is shown below.

The temperature difference between the top and bottom faces is higher with Ni than Cu.

 

The vectors of the heat flux are shown below.

 

When the heat flux is the same, the temperature gradient is steeper with lower conductive material.