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Home / Examples / Thermal Analysis [Watt] / Example 7: Heat Radiation by Forced Convection (Steady-State Analysis)

Example 7: Cooling by Forced Convection (Steady-State Analysis)


General

  • A heat source is placed on a substrate, and there is a forced air flow for cooling in parallel to the substrate. The heat radiation is analyzed under the steady-state condition.
     

  • The coefficient of heat transfer is acquired manually.
    To acquire it automatically, see "Ex.1 of Simple Fluid-Thermal Analysis".
     

  • The temperature distribution and the heat flux vectors are solved.
     

  • Unless specified in the list below, the default conditions will be applied.
     

  • Obtain this session's project file. (Right-click and choose 'Save link as')


  • Results will vary depending on Femtet version and the PC environment.

 

Analysis Space

Item

Settings

Analysis Space

3D

Model Unit

mm

 

Analysis Conditions

Item

Settings

Solver

Thermal Analysis [Watt]

Analysis Type

Steady-state Analysis

Options

N/A

Model

The substrate (VOL1) and the heat source (VOL2) are created as solid bodies, and the heat amount is defined in the body attribute of VOL2.

The coefficient of heat transfer for the top and bottom faces of the substrate and the top face of the heat source are calculated by the simplified equation and set to them.

Body Attributes and Materials

Body Number/Type

Body Attribute Name

Material Name

0/Solid

VOL1

006_Glass_epoxy *

1/Solid

VOL2

001_Alumina *

* Available from the material DB

 

The heat quantity of VOL2 is set up as follows.

Body Attribute Name

Tab

Settings

VOL2

Heat Quantity

1 [W]

Boundary Conditions

The coefficient of heat transfer for the forced convection are calculated as follows. See [Heat Transfer Coefficient for Forced Convection] for more information.

To acquire it automatically, see [Ex.1 of Simple Fluid-Thermal Analysis].
 

h = 3.86 x (V/L)0.5 x C [W/m2/deg]

 

where

Air flow V=1 [m/s]

Top and Bottom Faces of Substrate (VOL1): Typical length L=0.05, C=1 -> h=17.26
Top Face of Heat Source (VOL2): Typical length L=0.02, L'=0.015, C=1 * -> h=27.3

 

*

The thickness (d) of the speed boundary layer at the edges of the heat source is calculated as follows

 

δ=0.0182 x (L’/V)0.5= 2.3 [mm]

 

This is close enough to the thickness of heat source, so we set C=1.

 

Boundary Condition Name/Topology

Tab

Boundary Condition Type

Settings

BC1/Face

Thermal

Heat Transfer/Convection

Coefficient of Heat Transfer: 27.3 [W/m2/deg]

Ambient Temperature: 25 [deg]

BC2/Face

Thermal

Heat Transfer/Convection

Coefficient of Heat Transfer: 17.26 [W/m2/deg]

Ambient Temperature: 25 [deg]

Results

The temperature distribution is shown below.

 

A cross section's temperature distribution is shown below.