Home / Examples / Thermal Analysis [Watt] / Example 7: Heat Radiation by Forced Convection (Steady-State Analysis)
Example 7: Cooling by Forced Convection (Steady-State Analysis)

General
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A heat source is placed on a substrate, and there is a forced air flow for cooling in parallel to the substrate. The heat radiation is analyzed under the steady-state condition.
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The coefficient of heat transfer is acquired manually.
To acquire it automatically, see "Ex.1 of Simple Fluid-Thermal Analysis".
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The temperature distribution and the heat flux vectors are solved.
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Unless specified in the list below, the default conditions will be applied.
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Obtain this session's project file. (Right-click and choose 'Save link as')
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Results will vary depending on Femtet version and the PC environment.
Analysis Space
|
Item |
Settings |
|
Analysis Space |
3D |
|
Model Unit |
mm |
Analysis Conditions
|
Item |
Settings |
|
Solver |
Thermal Analysis [Watt] |
|
Analysis Type |
Steady-state Analysis |
|
Options |
N/A |
Model
The substrate (VOL1) and the heat source (VOL2) are created as solid bodies, and the heat amount is defined in the body attribute of VOL2.
The coefficient of heat transfer for the top and bottom faces of the substrate and the top face of the heat source are calculated by the simplified equation and set to them.

Body Attributes and Materials
|
Body Number/Type |
Body Attribute Name |
Material Name |
|
0/Solid |
VOL1 |
006_Glass_epoxy * |
|
1/Solid |
VOL2 |
001_Alumina * |
* Available from the material DB
The heat quantity of VOL2 is set up as follows.
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Body Attribute Name |
Tab |
Settings |
|
VOL2 |
Heat Quantity |
1 [W] |
Boundary Conditions
The coefficient of heat transfer for the forced convection are calculated as follows. See [Heat Transfer Coefficient for Forced Convection] for more information.
To acquire it automatically, see [Ex.1 of Simple Fluid-Thermal Analysis].
h = 3.86 x (V/L)0.5 x C [W/m2/deg]
where
Air flow V=1 [m/s]
Top and Bottom Faces of Substrate (VOL1): Typical length L=0.05, C=1 -> h=17.26
Top Face of Heat Source (VOL2): Typical length L=0.02, L'=0.015, C=1 * -> h=27.3
*
The thickness (d) of the speed boundary layer at the edges of the heat source is calculated as follows
δ=0.0182 x (L’/V)0.5= 2.3 [mm]
This is close enough to the thickness of heat source, so we set C=1.
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Boundary Condition Name/Topology |
Tab |
Boundary Condition Type |
Settings |
|
BC1/Face |
Thermal |
Heat Transfer/Convection |
Coefficient of Heat Transfer: 27.3 [W/m2/deg] Ambient Temperature: 25 [deg] |
|
BC2/Face |
Thermal |
Heat Transfer/Convection |
Coefficient of Heat Transfer: 17.26 [W/m2/deg] Ambient Temperature: 25 [deg] |
Results
The temperature distribution is shown below.

A cross section's temperature distribution is shown below.



