Example4 Heating of Conductive Strip (Steady-State Analysis)

General

  • In this exercise, the AC voltage of 100Hz is applied for the same model as Exercise 2.
     

  • The steady state after a long lapsed time is calculated.
     

  • There are no changes in the other conditions.
     

Analysis Conditions

In this exercise, the AC voltage of 100Hz is applied.

The time step which is set in the transient analysis tab should be shorter than one eighth of the AC voltage period ( 10[ms] / 8).

 

The difference from Exercise 2 is indicated by red letters in the table.

Tab

Setting Item

Settings

Transient analysis

Time step

Manual

Restart

Deselect

Time step

0.5^-3[s]

Calculation steps

20

Boundary Conditions

The difference from Exercise 2 is indicated by red letters in the following table.

Boundary Condition Name/Topology

Tab

Boundary Condition Type

Settings

T_Wall/Face

Thermal

Adiabatic

 

T0/Face

Thermal

Temperature

25[deg]

V0/Face

Electric

Electric wall

Waveform: Constant, Voltage: 0.00[V]

V1/Face

Electric

Electric wall

Waveform: Sine wave

Frequency: 100Hz

Voltage : Minimum -0.01V

Voltage : Maxmum +0.01V

Outer Boundary Condition *

Thermal

Heat Transfer/Ambient Radiation

Heat transfer coefficient: 10 [W/m2/deg]

Ambient temperature: 25[deg]

Click Check Waveform button on “Electric wall” tab in the boundary condition setting dialog for V1,

and the applied voltage will show up in graph form.

 

Results

The temperature at (5.5, 3.5, 1.1) is shown below.