Example25 Cylinder under Fixed Normal Displacement Subjected to Thermal Load

General

The model is a cylinder consisting of two different materials
Its normal displacement is fixed and subjected to the thermal load.
The deformation, the displacement and the mechanical stress are solved.
Unless specified in the list below, the default conditions will be applied.

The temperature is applied evenly on the model.

Select Thermal load and set the reference temperature and the reached temperature.

There is no need to couple with the thermal analysis [Watt].

Item	Settings
Solvers	Mechanical Stress Analysis [Galileo]
Analysis Type	Static analysis
Options	Select “Thermal load”.

The Step/Thermal Load tab is set as follows.

Tab	Setting Item	Settings
Step/Thermal Load	Reference temperature	0[deg]
Step/Thermal Load	Step/Reached Temperature Setting	Step 1: 300[deg]

The cylinder’s top and bottom faces are fixed in all directions. The side is fixed in normal displacement.

The upper and lower bodies have different coefficients of expansion.

The material properties are set up as follows:

Material Name	Tab	Properties
Mat1	Coefficient of Expansion	0x10^-6[1/deg]
Mat1	Elasticity	Young’s modulus: 1×10^9[Pa] Poisson’s ratio: 0.3
Mat2	Coefficient of Expansion	400×10^-6[1/deg]
Mat2	Elasticity	Young’s modulus: 1×10^9[Pa] Poisson’s ratio: 0.3

Boundary Condition Name/Topology

Tab

Boundary Condition Type

Settings

Fix/Face

Mechanical

Displacement

Select all X/Y/Z components.

UX=0, UY=0, UZ=0

SlideFree/Face

Mechanical

Normal displacement

0.0×10^-3[m]

The displacement diagram is shown below. The scale adjustment is “same scale”

Body2 is pushing up Body1.

The section at XZ plane is shown below.

The border has been moved upward translationally.