Example21 Piezoelectric Device with Polarization in Radius Direction

General

  • Voltage is applied to a piezoelectric device with polarization in radius direction.

  • How to set and check the polarization direction will be explained.
     

  • The deformation, the displacement distribution and the mechanical stress distribution are solved.

 

Analysis Conditions

Item

Setting

Solver

Piezoelectric Analysis [Rayleigh]

Analysis Space

3D

Analysis Type

Static analysis

Unit

mm

Options

N/A

Model

A model is a solid body. The boundary condition is set on the internal and external faces to specify voltage.

Body Attributes and Materials

Body Number/Type

Body Attribute Name

Material Name

0/Solid

Body_Attribute_Name_001

000_P-4 *

* Available from the Material DB

 

Body Attribute Name

Tab

Setting

Body_Attribute_Name_001

Direction

Specified by: Vector

Select “Use distribution data”

Edit Distribution Data dialog box

Distribution Dimension: 2D

Coordinate System: Local coordinates

Local Coordinates

Origin O’: 0.0,0.0,0.0 x10^-3

Vector O’X’: 1.0,0.0,0.0

Vector O’Y’: 0.0,0.0,1.0

No1. X’ Coordinate Y’ Coordinate X component Y component Z component
1 -10 -10 -1 0 -1
2 -10 10 -1 0 1
3 10 -10 1 0 -1
10 10 1 1 0 1

 

Exponent -3  
Unit [m]  

 

   

 

 

Boundary Condition

Boundary Condition Name/Topology

Tab

Boundary Condition Type

Setting

V0/Face

Electric

Electric wall

Voltage specified:

Voltage 0[V]

V1/Face

Electric

Electric wall

Voltage specified:

Voltage 1[V]

 

Results

Direction distribution is examined as follows.

Go to Results tab > Display > Solver > Mesh.

For Field, select Direction distribution. If Element Vector button is pressed, the polarization directions are indicated by arrows as in the below diagram.

As intended, the polarization has been set in the radius direction.

 

 

The displacement is examined as follows. Go to Results tab > Display > Solver > Piezoelectric analysis.

By selecting “Displacement” and “Magnitude”, a contour diagram is created as follows. The displacement on the inner area of the ring is larger than the outer area. It indicates the stretch in the circumferential direction and the shrinkage in the thickness direction.

 

The mechanical stress is examined with a vector diagram. The tensile stress is observed in the outer area and the compression stress in the inner area. The stresses are uniformly applied in the circumferential direction.