Example10 Hall Element Analysis

General

  • In the p-type (or n-type) semiconductor, the current flows in Z direction where the magnetic field exists in y direction.
    Charged particles move in x direction due to the Lorentz force.
    This results in Hall effect: the production of electric field perpendicular to both the current and the magnetic field.
     

  • The Hall voltage and the resistance are solved in this exercise.
     

  • Unless specified in the list below, the default conditions will be applied.
     

 

Analysis Space

Item

Settings

Analysis Space

2D

Model unit

mm

Analysis Conditions

The analysis space is 2D only for Hall element analysis.

Item

Settings

Solvers

Electric Field Analysis [Coulomb]

Analysis Type

Static analysis

Material Type

Conductor

Options

Select “Perform the Hall element analysis”.

 

Define the external magnetic field.

Tab

Setting Item

Settings

External magnetic field

External magnetic field

Y component: 79577[A/m]
(=1[Kgauss])

Model

A sheet body represents the device. The electrodes to apply the voltage and to monitor the Hall voltage are set on the circumferential edges.

Body Attributes and Materials

Body Number/Type

Body Attribute Name

Material Name

0/Sheet

HallDevice

HallDevice

 

Body Attribute Name

Thickness/Width

HallDevice

Thickness of Sheet Body: 3×10^-3[mm]

 

Material Name

Conductor wall

HallDevice

Conductivity Type: Semiconductor

Hall coefficient: 3.5×10^-4[m3/C]

Hall mobility: 7.4[m2/V/sec]

Boundary Conditions

Set voltages on V0 and V1. F1 and F2 are floating.

Boundary Condition Name/Topology

Tab

Boundary Condition Type

Settings

V0/Edge

Electric

Electric wall

Voltage specified, 0[V]

V1/Edge

Electric

Electric wall

Voltage specified, 1[V]

F1/Edge

Electric

Electric wall

Floating Electrode

F2/Edge

Electric

Electric wall

Floating Electrode

 

Results

To view the calculation results, go to the [Results] tab

 

 

 click [Table] .

 

The potential difference between F1 and F2 is the Hall voltage.

 

The isoline contour of the potential is shown below.

The contour’s division is set to “Equal spacing” and the division number is 20 on the Contour tab of Graphics Setup dialog box.

 

The vectors of the current density are shown below.

You can see that the distributions of potential and current are disturbed due to the Hall effect.